Chemistry, asked by salonitomar593, 1 year ago

100 gram of KNO3 heated to redness. Find volume of oxygen is liberated at 39°C and 765 torr pressure.

Answers

Answered by maskarasanket
8

2KNO3 ----. 2KNO2 + O2 - this balanced equation tells you that 2 moles of the nitrate makes 2 moles of nitrite and 1 mole of O2  

The nitrate molar mass = K + N +(3xO) = 39 +14 +(3x16) =  

101 g/mole. the molar mass of O2 is 32 g  

the equation say then that 2(101)g of nitrate will make 32 g O2 or 202 g will make 32 g O2  

If you start with 5 g KNO3, the amount of O2 you can make will be 5 X 32/202 = 0.792 grams O2  

Check: 32/202 = 0.15841; 5 X 0.15841 = 0.792 g. The volume of O2 you collect will depend on how you collect it and upon temperature and pressure.  

probably around 550 ml - but cannot be exact without more information

Answered by fawazalam091
0

Answer:

2KNO3 ----. 2KNO2 + O2 - this balanced equation tells you that 2 moles of the nitrate makes 2 moles of nitrite and 1 mole of O2  

The nitrate molar mass = K + N +(3xO) = 39 +14 +(3x16) =  

101 g/mole. the molar mass of O2 is 32 g  

the equation say then that 2(101)g of nitrate will make 32 g O2 or 202 g will make 32 g O2  

If you start with 5 g KNO3, the amount of O2 you can make will be 5 X 32/202 = 0.792 grams O2  

Check: 32/202 = 0.15841; 5 X 0.15841 = 0.792 g. The volume of O2 you collect will depend on how you collect it and upon temperature and pressure.  

probably around 550 ml - but cannot be exact without more information

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