Question

100 gram sample H2 S o4 required 80 gram of NaOH for complete neutralization.what is the percentage purity of H2SO4​

Answer 1

2 Naoh + H2SO4=NA2SO4 +2 HO

So two moles of NAOH ie., 2×58.44 gms reacts with one mole ie., 98 go of sulphuric acid

60 gm of hydroxide reacts with mass m of sulphuric acid

m=60×98/116.88 gms

the mass of 80% of pure acid is then 100* m /80