Physics, asked by sidroid4088, 11 months ago

100 grams of ice is mixed with 100 grams of water final temparature of the mixture would be

Answers

Answered by abhi178
0

final temperature of mixture is 0°C

100g of ice at 0 degrees celsius is mixed with 100 grams of water at 80 degree Celsius the final temperature of the mixture will be....

mass of ice , m = 100g at 0°C

mass of water , m = 100g at 80°C

here heat flows through water to ice.

so, heat lost by water to reduce its temperature 0°C = mS∆T

= 100g × 1cal/g/°C × (80 - 0)

= 8000cal

heat gained by ice to melt the ice completely = mL = 100g × 80cal/g = 8000cal

here you can see that, heat lost by water to reduce temperature to 0°C is equal heat gained by ice to melt the ice completely.

hence, final mixture is water at 0°C .

so, temperature of mixture will be 0°C.

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Answered by Anonymous
0

\huge\bold\purple{Answer:-}

here heat flows through water to ice. here you can see that, heat lost by water to reduce temperature to 0°C is equal heat gained by ice to melt the ice completely. hence, final mixture is water at 0°C . so, temperature of mixture will be 0°C

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