100 grams of ice is mixed with 100 grams of water final temparature of the mixture would be
Answers
final temperature of mixture is 0°C
100g of ice at 0 degrees celsius is mixed with 100 grams of water at 80 degree Celsius the final temperature of the mixture will be....
mass of ice , m = 100g at 0°C
mass of water , m = 100g at 80°C
here heat flows through water to ice.
so, heat lost by water to reduce its temperature 0°C = mS∆T
= 100g × 1cal/g/°C × (80 - 0)
= 8000cal
heat gained by ice to melt the ice completely = mL = 100g × 80cal/g = 8000cal
here you can see that, heat lost by water to reduce temperature to 0°C is equal heat gained by ice to melt the ice completely.
hence, final mixture is water at 0°C .
so, temperature of mixture will be 0°C.
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here heat flows through water to ice. here you can see that, heat lost by water to reduce temperature to 0°C is equal heat gained by ice to melt the ice completely. hence, final mixture is water at 0°C . so, temperature of mixture will be 0°C