100 J of heat are produced each second in a 2.5Ω resistance. Find potential difference across the resistor?
Answers
Answered by
5
Given :-
i) Heat energy (H) = 100 J
ii) Time (t) = 1 second
iii) Resistance (R) = 2.5 Ω
To find:-
i) Potential difference (V) = ?
Formula to be used :-
i) H= I²Rt
Solution :-
∵ H = I²Rt.........(1)
And by Ohm's Law,
V = I * R
∴ I = V/R..........(2)
Substituting eqn 2 in eqn 1, we get
∴ H = (V/R)² * R * t
H = V² * t / R
∴ V² = H*R / T
∴ V² = 100 * 2.5 / 1
∴ V² = 250
∴ V = √250
∴ V = 5√10 Volts.
Hope this helps you !!
i) Heat energy (H) = 100 J
ii) Time (t) = 1 second
iii) Resistance (R) = 2.5 Ω
To find:-
i) Potential difference (V) = ?
Formula to be used :-
i) H= I²Rt
Solution :-
∵ H = I²Rt.........(1)
And by Ohm's Law,
V = I * R
∴ I = V/R..........(2)
Substituting eqn 2 in eqn 1, we get
∴ H = (V/R)² * R * t
H = V² * t / R
∴ V² = H*R / T
∴ V² = 100 * 2.5 / 1
∴ V² = 250
∴ V = √250
∴ V = 5√10 Volts.
Hope this helps you !!
Answered by
3
Answer:
P=v²/r =v²=P x R =1000w x 2.5 resistance.
Explanation:
v² =2500
v=under root 2500
v=50.
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