Question

100 J of heat is produced each second in a 4Ω resistor. The potential difference across the resistor will be:

Answer 1

Answer:

The answer will be 20 volt.

Explanation:

Given,

         Heat = 100J;

         Resistance = 4 ohm;

         Time = 1 second;

According to Joule's Law,

                                            H = $I^{2} RT$ ;

                                            H = $\frac{V^{2} }{R} T$                  ( by V = IR )  (i)

Now put the value of given variables in equation (i);

So,                           ⇒ 100 =  $\frac{V^{2} }{4} 1$ ;                   (here, T is 1 because we are asked for every second.)

                               ⇒ 400 = $V^{2}$

                              ⇒ V = $\sqrt{400}$  = 20 V

Therefore, the potential difference will be 20 V when 100 J of energy is released every second in a resistor of resistance 4 ohm.

Answer 2

Answer:

20V

Explanation:

Given,

        Heat = 100J;

        Resistance = 4 ohm;

        Time = 1 second;

According to Joule's Law,

                                           H = (I^2)Rt ;

                                           H = (V^2/R)t                  ( by V = IR )  (i)

Now put the value of given variables in equation (i);

So,                           ⇒ 100 =  V^2/R  ;                   (here, T is 1 because we are asked for every second.)

                              ⇒ 400 = V^2

                             ⇒ V =   = 20 V

Therefore, the potential difference will be 20 V when 100 J of energy is released every second in a resistor of resistance 4 ohm.