100 men took a dip in a pond 50 m long and 18 m wide. If the average displacement of water by a man was
3.6 m3, then calculate the rise in the water level.
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Answer:
water level=40cm
Given
100 men took a dip in a pond 50 m long and 18m wide .If the average displacement of water by a men was 3.6 m cube then calculate
Step-by-step explanation:
Given
100 men took a dip in a pond 50 m long and 18m wide .If the average displacement of water by a men was 3.6 m cube then calculate the rise in the water level
Displacement of water by 1 man = 3.6 m^3
Total volume of water displaced by 100 men = (3.6 x 100) m^3 = 360 m^3
Rise in water level in a pond is same as the height of volume of cuboid.
Volume = Length x Breadth x height
So rise in water level = 360 / (50 x 18)
= 360 / 900
= 0.4 m
= 40 cm
The rise in the water level is 40 cm
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