Math, asked by mdzishan5192, 4 months ago

100 men took a dip in a pond 50 m long and 18 m wide. If the average displacement of water by a man was
3.6 m3, then calculate the rise in the water level.​

Answers

Answered by adyapattnaik25
1

Answer:

water level=40cm

Given

100 men took a dip in a pond 50 m long and 18m wide .If the average displacement of water by a men was 3.6 m cube then calculate

Step-by-step explanation:

Given

100 men took a dip in a pond 50 m long and 18m wide .If the average displacement of water by a men was 3.6 m cube then calculate the rise in the water level

Displacement of water by 1 man = 3.6 m^3

Total volume of water displaced by 100 men = (3.6 x 100) m^3 = 360 m^3

Rise in water level in a pond is same as the height of volume of cuboid.

Volume = Length x Breadth x height

So rise in water level = 360 / (50 x 18)

= 360 / 900

= 0.4 m

= 40 cm

The rise in the water level is 40 cm

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