Question

100 metre by 06 metre find rectangle

Answer 1

Answer:

Let the length and breadth of the rectangle be x and y

Perimeter of rectangle P=2(x+y)

100=2(x+y)

⇒x+y=50 ....(1)

Area A=xy

A=x(50−x)

dx

dA

=50−2x

For maximum or minimum,

dx

dA

=0

⇒x=25

Now,

dy

2

d

2

A

=−2<0

Thus, A is maximum at x=25

Hence, area is maximum at x=25,y=25

Explanation:

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