100 mg mass of nichrome metal is drawn into a wire of area of cross-section 0.05 m m 3 . Calculate the resistance of this wire. Given density of nichrome 8.4 x 10 3 kg/ m 3 and resistivity of the material as 1.2 x 10 - 6 Ω m
Answers
Given that
Mass of Nichrome metal = 100 mg = 100/10^6 KG. = m
Cross section Area of wire drawn = 0.05 Square mm = 0.05/1000000 square meter. = A
Density of Nichrome = 8400 Kg/m^3 = D
Resistivity of the material = 1.2/10^6 Ωm = I
Volume = Mass/Density = 100 * 10^-6 / (8400) = 12x10^-9 cubic meters.
Volume = Area*Length
Therefore Length = 12x10^-9 / 5x10^-8 = 0.24 m = L
Consider Resistance ( R ) = I*(L/A)
= 1.2 * 10^-6 * 0.24 / (5x10^-8) = 1.2 * 100 * 0.24 / 5 = 5.76Ω
Resistance of wire = 5.76Given that
Mass of Nichrome metal = 100mg = 100/10^6 KG. = m
Cross section Area of wire drawn = 0.05 Square mm = 0.05/1000000 square meter. = A
Density of Nichrome = 8400 Kg/m^3 = D
Resistivity of the material = 1.2/10^6 Ωm = I
Volume = Mass/Density = 100 * 10^-6 / (8400) = 12x10^-9 cubic meters.
Volume = Area*Length
Therefore Length = 12x10^-9 / 5x10^-8 = 0.24 m = L
Consider Resistance ( R ) = I*(L/A)
= 1.2 * 10^-6 * 0.24 / (5x10^-8) = 1.2 * 100 * 0.24 / 5 = 5.76Ω