Question

100 millilitres of ethyl alcohol and 900 ml of water are mixed to form 1 litre solution the molarity and molality of the resulting solution are ​

Answer 1

Answer:

the  molarity is 2M and molality is 2.2 m please mark me as brainliest

Explanation:

Given: 100ml of Ethyl alcohol and 900 ml of water

Mass of ethyl alcohol present: Mass= Density*Volume= 100*0.92=92g

Mass of water present= 900g.

No. of moles of ethyl alcohol; Given mass/molecular mass of ethyl alcohol=92/46= 2 moles

Molarity= No. of moles of solute/1 litre of solution

=2/1 = 2M

Therefore molarity= 2M.

Molality = No. of moles of solute in 1k of Solvent

In 900 g of water, 92 g of ethyl alcohol is present.

In 1g of water, 92/900 g of ethyl alcohol is present.  

Therefore, in 1000 g of water, (92/900) * 1000g of ethyl alcohol is present.

= 102.22 g

Therefore number of moles = 102.22/46

=2.22 ( approx )

therefore molality = 2.2m