Chemistry, asked by Programme, 10 months ago

100 mL 0.1 M HCl was mixed with 150 mL 0.1 M HNO3. What volume of 0.1 M NaOH will be needed for complete neutralisation of the mxiture?

Answers

Answered by siyona1603
8

158 mL

158 mL of 0.1 M of HCl is required to react completely with 0.1 M mixture of NaOH, containing equimolar amounts of both.

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Answered by Jasleen0599
15

Given:

Molarity of all the compounds, M1 = M2 = M3 = 0.1 M

V1 = 100 ml

V2 = 150 ml

To Find:

The volume of NaOH needed for complete neutralization.

Calculation:

- Since HCl and HNO3 both are monobasic acids, hence we can simply add their volumes.

- Now using molarity equation, we get:

M1 × (V1 + V2) = M3 × V3

⇒ 0.1 (100 + 150) = 0.1 × V3

V3 = 250 ml

- So, we need 250 ml of NaOH for the complete neutralization of the mixture.

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