Question

100 ml each of 1M AgNO3 and 1M NaCl are mixed.The nitrate ion concentration in the resulting solution is

Answer 1

Answer: 0.5 moles/L

Explanation:

$AgNO_3+NaCl\rightarrow AgCl+NaNO_3$

$\text{no of moles of} AgNO_3={\text{Molarity}\times {\text{Volume in L}}$

$\text{no of moles of} AgNO_3={1M}\times {0.1L}=0.1moles$

$\text{no of moles of} NaCl={\text{Molarity}\times {\text{Volume in L}}$

$\text{no of moles of} NaCl={1M}\times {0.1L}=0.1moles$

As 1 mole of $AgNO_3$ combines with 1 mole of $NaCl$ to give 1 mole of $NaNO_3$

0.1 mole of  $AgNO_3$ combines with 0.1 mole of $NaCl$ to give 0.1 mole of $NaNO_3$

Concentration of $NO_3^{-1}$=$\frac{\text {no of moles}}{\text {total volume in Liters}}$

Concentration of $NO_3^{-1}$=$\frac{0.1}{0.2L}=0.5moles/L$

Answer 2

Explanation:

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