Question

100 ml of 0.1 m h2so4 is exactly neutralized by 100 ml of naoh solution. calculate the molarity of naoh solution

Answer 1

The equation for the reaction is :

H₂SO₄(aq) + 2NaOH (aq) —> Na₂SO₄(aq) + 2H₂O(l)

The mole ratio of sulphuric acid to sodium hydroxide is :

1 : 2

0.1 moles —> 1000ml

? —> 100ml

(100/1000) × 0.1 = 0.01 moles

Since the mole ratio is 1 : 2 the moles of sodium hydroxide are:

0.01 × 2 = 0.02 moles

0.02 moles are in 100 ml

How many moles are in 1000

1000/100 × 0.02 = 0.2M

Molarity of sodium hydroxide is %

0.2 M