100 ml of 0.1 M H2So4 with 50 ml of 0.1 M of NaOH find normality
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Answer:Molarity of the resulting solution=M1V1+M2V2/V1+V2
0.1*100+0.1*50/150 ................... ( 100 ml+50 ml)
M resulting=15/150=0.1 M
Normality=Molarity*Valency
hence, in H2So4-valency=2; N1=0.1*2=0.2 N
Valency of Naoh=1 ; N2=0.1*1=0.1 N
N resulting=N1V1+N2V2/V1+V2
=0.2*100+0.1*50/150
=25/150 =1/6 =0.16 N.
Explanation:
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