100 mL of 0.1 M HCl is diluted to 0.01M. What s the volume of H2O to be added to get the concentration.
Please answer within 5 min... Very urgent.
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Answer:
When you add two different concentrations of same strong acid, the pH contribution will be from both concentrations.
M
1
=0.1M,V
1
=100ml
M
2
=0.01M,V
2
=100ml
Final volume of solution is 100+100=200ml
The final concentration of mixture will be calculated as
MV=M
1
V
1
+M
2
V
2
⇒M(100+100)=0.1×100+0.01×100
M=
200
(10+1)
=0.055M
pH=−log[H
+
]=−log(0.055)=1.259∼1.
Explanation:
When 0.1 M HCl solution is diluted 100 times, the molarity of solution will be
100
0.1
=0.001M.
HCl is strong electrolyte. It completely dissociates.
Its hydrogen ion concentration will be 0.001 M.
The pH of the solution will be −log[H
+
]=−log(0.001)=3.
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