Question

100 ml of 0.1 M solution of solute A is mixed with 200 ml of 0.1 M solution of solute B .If A and B are non reacting substances, the molarity of the final solution will be
A. 0.3 M
B. 0.4 M
C. 0.1 M
D. 0.15 M​

Answer 1

Answer:

molarity = no. of moles/volume in litre

use this to find total no. of moles

moles of solution A

0.1 = n x 1000/100

n = 0.01

moles of solution B

0.1 = n x 1000/200

0.1 = n x 5

n = 0.02

add n of both the solution = total n = 0.01 + 0.02

= 0.03moles

total volume = 100 + 200 = 300ml = 0.3litre

final molarity = 0.03/0.3 = 0.1M

thus the final molarity = 0.1M