100 ml of 0.2 m naoh solution is mixed with 100ml of 0.1m hcl solution. the molarity of naoh in the solution after the reaction is
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0
Explanation:
Answer
NaOH+CH
3
COOH⟶CH
3
COONa+H
2
O
10 m mol 20 m mol
0 10 m mol 10 m mol
Now it is a buffer
pH=pk
a
+log[
acid
salt
]
pH=4.74+log1=4.74
Answered by
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Answer:
answer is 0.05 M
Explanation:
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