Question

100 ml of 0.3 m hcl is mixed with 200ml of 0.3mh2so4 solution find molarity of h+in resultant solution

Answer 1

M1 = 0.3 mol/L

V1 = 100ml = 0.1L

M2 = 0.3 mol/L

V2 = 200ml = 0.2L

Now,

(M1 X V1) + (M2 X V2) = M3(V1 + V2)

0.03 + 0.06 = M3(0.3)

M3 = 0.09/0.3 = 0.3 mol/L

HCl will dissociate into H⁺ and Cl⁻

Molarity of H⁺ = 0.3 mol/L