Question

100 ml of 0.3 m hcl solution is mixed with 100 ml of 0.333 m koh solution. the amount of heat liberated is

Answer 1

234kj .......is the right answer

Answer 2

Given: 100mL of 0.3M HCl mixed with 100mL of 0.333M KOH.

To find: the amount of heat liberated.

Step-by-step explanation:

Step 1 of 1

1 M of KOH reacts with 1M of HCl to produce 57.3 kJ of heat.

The milliequivalents of both KOH and HCl:

$M_{eq}KOH =0.3*1*100=30\\\\M_{eq}HCl =0.333*1*100=33.3$

1000 milliequivalents of KOH on neutralization liberate 57300 J of heat.

Hence, the heat liberated by the neutralization of 30 milliequivalents of KOH is:

$=\frac{57300*30}{1000} \\\\=1719J$

The amount of heat liberated is 1719J.