Question

100 ml of 0.3m hcl solution is mixed with 200 ml of 0.3 m h2so4 solution. what is the molarity of h + in the resultant solution?

Answer 1

Molarity = no of moles of solute[H+]/ volume of solution

No of moles of [H+] for HCl = 0.3*0.1 = 0.03

No of moles of [H+] for H2SO4 = 0.2*2*0.3 = 0.12 (since there are two moles of H+ in a mole H2SO4

Total no of moles of [H+] = 0.15

Total volume of solution = 300ml = 0.3L

Thus Molarity = 0.15/0.3 = 0.5moles/L

Answer 2

Heya mate

Molarity=No of moles of solute [H+]/

Volume of solution

No of moles of [H+] for HCI=0.3*0.1=0.3

No. Of moles of [H+] for H2SO4 =0.2*2*0.3=0.12(since there are two moles H+ in a mole H2SO4

Total no. Of moles of [H+] =0.15

Total volume of solution =300 ml=0.3 L

Thus molarity =0.15/0.3=0.3=0.5moles/L