100 ml of 0.3N hcl solution is mixed with 200 ml of 0.6N h2so4solution what is the normality of h2so4 in final solution
Answers
Answered by
6
Using eqn N1V1+N2V2=N3V3
So, 0.3×100+0.6×200=N3×300
now, 30+120=N3×300
150÷300=N3
N3=1÷2=0.5N
So, 0.3×100+0.6×200=N3×300
now, 30+120=N3×300
150÷300=N3
N3=1÷2=0.5N
Similar questions