Question

100 ml of 1 m naoh is mixed with 50 ml of 1 n koh solution . normality of mixture is

Answer 1

Normality of the mixture would be 1 n ...
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Answer 2

Answer: The normality of the mixture is 1 N.

Explanation:

To calculate the normality of the solution after mixing 2 solutions, we use the equation:

$N=\frac{N_1V_1+N_2V_2}{V_1+V_2}$

where,

$N_1\text{ and }V_1$ are the normality and volume of the NaOH.

$N_2\text{ and }V_2$ are the normality and volume of the KOH.

We are given:

$N_1=1N\\N_2=1N\\V_1=100mL\\V_2=50mL$  

Putting all the values in above equation, we get:

$N=\frac{(1\times 100)+(1\times 50)}{100+50}\\\\N=1N$

Hence, the normality of the resulting solution is 1 N.