Question

100 ml of 3 mol H2 SO4 reacts with 100 ml of a
NaOH. Enthalpy of neutralisation of reaction
vith 100 ml of 3 mol
reaction wil​

Answer 1

h2so4*3 *na2(oh)2

this will the reaction

Answer 2

Answer:

-57.1 Kj.

Explanation:

From the question we know that the same amount of acid H2SO4 and same amount of bas NaOH os used. According to the equation 100 ml of 3 mol H2SO4 with 100 ml of 3 mole NaOH is mixed.

Since, the enthalpy of neutralisation for equivalent amount of acid and base is the energy evolved as -57.1 Kj. So, for this reaction the enthalpy of neutralisation is -57.1 Kj.