Question

100 ml of a sample of H2O2 by dissociation yielded 560 ml O2 at 00C and 1 atm. The molarity of H2O2 sample is : 1) 0.5 M 2) 1 M 3) 2.5 M 4) 0.75 M

Answer 1

Answer:

Explanation:

100ml H2O2 -------> 560ML O2

1ml ------> 5.6ml

We know that

11.2 M = vol strength

          = 5.6

     M = 1/2 = 0.5

Answer 2

Answer:

The molarity of H₂O₂ sample  is equal to 0.5M.

Therefore, the option (1) is correct.

Explanation:

The dissociation reaction of hydrogen peroxide:-

 2H₂O₂  $\longrightarrow$    2H₂O    +     O₂ (g)

Given, the volume of hydrogen peroxide (H₂O₂) = 100ml = 0.1L

100ml of hydrogen peroxide (H₂O₂)  yielded = 560ml of  O₂

Then 1 ml of H₂O₂ will give oxygen $=\frac{560}{100}=5.6ml$ of O₂ gas

The volume strength of solution = 5.6V of H₂O₂

Volume strength = 11.2 × molarity

Molarity of H₂O₂ sample solution $=\frac{volume\; strength}{11.2}$

Molarity =  5.6/11.2

Molarity of H₂O₂ solution = 0.5M.

Therefore, the molarity of the given solution of hydrogen peroxide is 0.5M.