Question

100 ml of a solution of sodium hydroxide is found to be completely neutralized by 80 ml of given solution of HCL to form a true solution of sodium chloride salt what will be the amount of hydrochloric acid required to neutralize 200 ml of the same solution of sodium hydroxide​

Answer 1

Answer :-

Given That

100 ml of sodium hydroxide is neutralized by 80ml of

HCl .

And , There is 200ml of Sodium hydroxide.

Let the HCl required be X

We know Ratio is always proportional.

So,

100/80 = 200/X

X = (200 × 80)/100

X = 2 × 80

X = 160

Hence, 160ml of HCl is required to neutralize 200ml of NaOH (sodium hydroxide)