100 ml of a water sample required 20ml of 0.01M EDTA for titration with EBT indicator.100ml of the same water sample after boiling and filtering required 10ml of 0.01M EDTA.Calculate the total carbonate and non-carbonate hardness of the sample.
Answers
Answer:
100 mL sample of hard water is titrated with 500 " mL of " 0.001 M EDTA solution at
, using eriochrome black-T indicator to reach equivalence point. An equal another amount of hard water sample is boiled for 30 min. After filtration and cooling, the same sample is titrated with 200 " mL of " 0.011 M EDTA solution at
using Mg-EDTA complex solution and erichrome black-T indicator to reach equivalence point. <br> (i). Calculate the total hardness of water sample (temporary
permanent) in ppm of
. <br> (ii). Calculate the permanent hardness of water sample in ppm of
. <br> (iii). Calculate the temporary hardness of water sample in ppm of
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Answer:
The total carbonate and noncarbonate hardness of the sample is 200ppm.
Explanation:
Solution :
100ml water sample required 20 ml of 0.01 M EDTA
Total hardness=Ca2+
⇒ M1V1=M2V2
20*0.01= M2*100
M2=.002 (Ca2+)
Total hardness =.002*10^6*10^2/10^3
=200ppm
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