Chemistry, asked by agathamudikishore, 10 months ago

100 ml of an aqueous solution contains 6.023 x 10 power 22 solute molecules. Then the molarity of solution is

Answers

Answered by shyamajoshi04
6

Answer:

Explanation:

As we know

1mole=6.023×10^23molecules

1molecule=1/6.023×10^23 mole

So here we have 6.023×10^22molecules whchi will give

1/6.023×10^23×6.023×10^22/1mole

=0.1 mole

Now molariry=mole/ vol

0.1/0.1l=1M

So here is the answer

Hpe it will help u

Answered by sardarg41
2

Answer:As we know

1mole=6.023×10^23molecules

1molecule=1/6.023×10^23 mole

So here we have 6.023×10^22molecules whchi will give

1/6.023×10^23×6.023×10^22/1mole

=0.1 mole

Now molariry=mole/ vol

0.1/0.1l=1M

Explanation:

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