100 ml of liquid A (density = 1200 kg m ^(-3)) and 100 g of liquid B (density = 0.8 g cm^(-3)) are mixed to form a homogeneous mixture. Assuming that tow liquid do not chemically react with each other, find density of the resultant mixture.
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100 ml of liquid A(density = 1200 kg m^-3) and 100 g of liquid B(density = 0.8 g cm^-3) are mixed to form a homogeneous mixture. Assuming that the two liquid do not chemically react with each other, find the density of the resultant mixture
Explanation:
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Answer:
Density = Total mass/Total Volume
= 44/45 g/cm³
Explanation:
Density of A in g cm^-3 (Da) =
=1200 kg/m³ × (1m/100cm)³× 1000g/kg
=1200 × 1000g/m³ × 1m³/1000000cm³
=12× 10^5 × 10^6 g/cm³
=12× 1/10 g/cm³
=1.2 g/cm³
Mass of A = Density × Volume =1.2 g/cm³ × 100cm³
= 120g
since 1cm³ = 1ml
Volume of B = Mass / Density
= 100g/ 0.8g/cm³ = 125cm³
Density of Total mixture = Total mass/Total Volume
= (120g+ 100g)/(100cm³+125g/cm³)
= 220g / 225cm³
= 44/45 g/cm³
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