Question

100 ml of n 10 hcl 50 ml of n 2 h2so4 and 200 ml of N/10 Naoh solutions are mixed and volume is made one litre then normality of resulting solution and its nature will be...
1. 0.25 N
2. 0.015N
3. 0.45
4. 0.10

Answer 1

Answer:

0.055 normal of the solution.

Explanation:

The total volume to be made is 1 litre which is 1000 litre hence now for each of the compounds the value of the mass*volume will be 100*1/10 = 10 millimoles for HCl,

For H2SO4 50*1/2 = 25 millimoles of H2So4 and 1/10*200 = 20 millimoles of NaOH so the total millimoles will be 20+25+10 = 55 of equivalent millimoles.

Now, the final mixture will be of 1000 litre and N normality so the  value of N will be 55/1000 = 29/200 = 0.055 normal of the solution will be formed.