Question

100 mL of O2(g) effuse from a porous container in 140 sec. 75 mL of unknown gas effuse under the similar conditions of temperature & pressure in 210 sec. The unknown gas is

Answer 1

Explanation:

From Graham's law of diffusion,

r

2

r

1

=

M

1

M

2

=

t

1

t

2

t

10

=

M

x

32

⇒

t

M

x

=

2.5

2

∴M

x

=2,t=2.5

Hence H

2

is the gas x and time is 2.5 sec

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Answer 2

Answer:

The unknown gas is O2 oxygen

Explanation:

From Graham's law of diffusion,

r2r1=M1M2=t1t2

t10=Mx32⇒tMx=2.52

∴Mx=2,t=2.5

Hence H2 is the gas x and time is 2.5 sec.

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