Chemistry, asked by TanishqGiri0, 1 year ago

100 ml of water at room temperature of 25 degree Celsius is taken in a beaker and a little of solid S dissolved in it by stirring to obtain a solution X. more of a solid S as is added to the solution with constant stirring while keeping the temperature of the solid constant at 30 degree Celsius .after sometime it is observed that no more solid dissolves in water and at the same time ,some solid is also left and undissolved at the bottom of the beaker. the contents of the beaker are filtered through a filter paper to obtain solution Y in the form of filterate.

A.)what is a solution like Called?

B.)what is solution like Y called?

C.)what will you observe if the solution Y at 30 degree celsius is cooled down to 10 degree Celsius by keeping the breaker in crushed ice.

D.)what term is used to denote the solid dissolved in 100grams of water in a solution like Y?

Answers

Answered by junnu1234
0
sorry i cant understand your question

TanishqGiri0: ok no problem
TanishqGiri0: hey i hoped that ud answered the question but when i looked u said i didnt understand?!!!!!!!!!!
junnu1234: yes
Answered by Ameyzode
0

a) saturated solution

b)unsaturated solution

c)the solute which you have dissolved will come in form of crystals

d)solute

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