100 mL of water was added dropwise to 100 g of dry soil, kept on filter paper in a funnel. The amount of water collected in graduated cylinder was found to be 60 mL. Calculate the percentage of water absorbed by the soil.
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multiply to 100 or 60 then answer will came
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Weight of soil = 50g
Initial volume of water in the measuring cylinder in mL = U
Final volume of water in the measuring cylinder in mL = V
Therefore, the volume of water absorbed by the soil in mL = (U – V)
Weight of water absorbed by the soil in g = (U – V)
Note: (1 mL of water has a weight equal to 1 g)
Percentage of water absorbed = (U - V) / 50 × 100%
In general, we can write,
Percentage of water absorbed = (U−V)W×100%
where,
U - Mass of the initial volume of water in the measuring cylinder in g
V - Mass of final volume of water in the measuring cylinder in g
W- Mass of sand in g
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