Question

100 ohm resistor and a 0.8 h inductor connected in series it is it an AC source due to which current in circuit equal to 0.7 sin 330 + 5 by 6 what is RMS voltage across inductor

Answer 1

Answer:

Explanation:I=0.7sin(300t+π/6) is the current in the circuit which is equal to I°sin(wt+¶).

This gives us the values of peak value of current I°=0.7 A. And w=300rad/s.

Now resistance across the inductor Xl=LW

=300×0.8

=240 ohms.

Now peak EMF is V°=I°Xl

=O.7×240

=168 Volts

Erms

=E°/√2

=168/1.414

=118.8 Volts..

Hope this helped you....