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a car accelerates from rest at constant rate (alpha) for some time, after which it decelerate at a constant rate (beta), to come to rest. if the volume elpased at t. evalute (1) max. velocity attained (2) total distance travelled.
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Answers
Answered by
8
Answer:
for the first leg of journey
v=0+at1
so. v=at1
for the second leg of journey of duration t-t1
0=v-beta (t-t1)
0= at1- beta T +beta T
t1=betaT/(a+b)
v= at1= a beta T/( a+b).
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Answered by
30
Let the car accelerate for time travelling distance and acquiring maximum velocity v.
Note: Check attachment no. 1
After this car decelerates for time to come to rest.
Note: Check attachment no. 2
Also:
Total distance travelled:
Attachments:
Anonymous:
Hm
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