Question

❤❤100 points ❤❤

Determine the H.C.F of the following no. by using algorithm (i - x ).

1) 300 , 450
2) 399 , 437
3) 1045 ,1520

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Answer 1

Answer:

Hello mate❤️❤️

1)here,

450>300

•°•450=300×1+150

300=150×2+0

°•°r(x)=0

H.C.F(450,300)=150

2)here,

437>399

•°•437=399×1+38

399=38×10+19

38=18×2+0

°•°r(x)=0

H.C.F(399,437)=18

3)here,1520>1045

1520=1045×1+475

1045=475×2+95

475=95×5+0

°•°r(x)=0

H.C.F(1520,1045)=95

Answer 2

$\rule{200}3$

$\color{red}\huge{\underline{\underline{\mathfrak{Question:-}}}}$

Determine the H.C.F of the following no. by using algorithm (i - x ).

1) 300 , 450

2) 399 , 437

3) 1045 ,1520

$\rule{200}3$

$\color{blue}\huge{\underline{\underline{\mathfrak{Answer}}}}$

1. 2
2. 19
3. 95

$\rule{200}3$

$\color{orange}\huge{\underline{\underline{\mathfrak{Solution:-}}}}$

1) 300 and 450

${\blue{\bold{\text{450 is greater}}}}$

450=300×1+150

300=150×2+0

So, HCF of 450 and 300 is 2

2) 399 and 437

${\blue{\bold{\text{437 is greater}}}}$

437=399×1+38

389=38×10+19

So, the HCF is 19

3) 1045 and 1520

${\blue{\bold{\text{1520 is greater}}}}$

1520=1045×1+95

1045=95×5+0

So, the HCF is 95

$\rule{200}3$

Hope it helps