Question

100 points for a well explained ans....​

Answer 1

⭐《ANSWER》

$\huge\mathfrak{\underline {\underline\pink {ANSWER}}}$

↪Actually welcome to the concept of the KINEMATICS

↪Basically here , we can see that ,

↪As here the frictional force is zero , so the only applied force is only acting on it ,

↪thus in the first case , where only BLOCK A is present , we get as ,

↪F = mA ( a)

...where, a is the acceleration ,

↪thus in the second case , As there are both BLOCK A and BLOCK B , the acceleration becomes a/5

↪so we get as ,

↪F = (mA + mB ) a/ 5

↪so combining we get as ,

〽⭐mA:mB = 1:4

Answer 2

The force that does the accelerating presumably stays the same. The acceleration rate drops by the same ratio that the total mass rises. That ratio is 5.

(MB + MA)/MA = 5

MB = 4 MA

Hope this helps! Thank you!