Question

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give full explanation...​

Answer 1

Torque from the centre of Rotation we get,

T = I*a

a is angular accln.

F*R = ((2/5)MR^2 + MR^2)a

we get a = 5F/7MR rad/sec.

Now accln. = a/R

Hence Acom = 5F/7M

where F is the tangential constant Force

Answer 2

$\huge\mathfrak\purple{Hello\:Mate}$❤

Torque from the centre of rotation we get, t = l × a

where a is angular acceleration.

F × R = [(2/5)MR^2 + MR^2]a

We get,

a = 5F/7MR rad/sec.

Now acceleration = a/R

Hence acom = 5F/7M

(where F is tangential constant force)

$\bold{@PhilophobiaXD}$✌