100 POINTS!!!!!!!!!! help me with this question plz ..I want both answer with explanation....
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1.
Slope of the line joining the points (-4,4) and (6,-1) is
m =(y2 - y1) / (x2 - x1) = -1/2.
The equation of the line is x +2y + 4 = 0
x = p and y = 1.
p + 2 + 4 = 0
p = -6.
2.
Let's split the quadrilateral ABCD into two triangles as ∆ABC and ∆ACD.
A (-3,1) , B (-2,-4) , C (4,-3) and D (3,4).
ar(∆ABC) = (1/2) [-3(-4 + 3) - 2(-3 -1) + 4(1 + 4)]
ar(∆ABC) = 15.5 units square.
ar(∆ACD) = (1/2) [-3(-3-4) + 4(4-1) + 3(1+4)]
ar(∆ACD) = 22.5 square units.
Area of quadrilateral ABCD = 15.5 + 22.5
= 38 units square.
-WonderGirl
Slope of the line joining the points (-4,4) and (6,-1) is
m =(y2 - y1) / (x2 - x1) = -1/2.
The equation of the line is x +2y + 4 = 0
x = p and y = 1.
p + 2 + 4 = 0
p = -6.
2.
Let's split the quadrilateral ABCD into two triangles as ∆ABC and ∆ACD.
A (-3,1) , B (-2,-4) , C (4,-3) and D (3,4).
ar(∆ABC) = (1/2) [-3(-4 + 3) - 2(-3 -1) + 4(1 + 4)]
ar(∆ABC) = 15.5 units square.
ar(∆ACD) = (1/2) [-3(-3-4) + 4(4-1) + 3(1+4)]
ar(∆ACD) = 22.5 square units.
Area of quadrilateral ABCD = 15.5 + 22.5
= 38 units square.
-WonderGirl
URGENT111:
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You're most welcome
Answered by
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1.Slope of the line joining the points (-4,4) and (6,-1) is
m =(y2 - y1) / (x2 - x1) = -1/2.
The equation of the line is x +2y + 4 = 0
x = p and y = 1.
p + 2 + 4 = 0
p = -6.
2.Let's split the quadrilateral ABCD into two triangles as ∆ABC and ∆ACD.
A (-3,1) , B (-2,-4) , C (4,-3) and D (3,4).
ar(∆ABC) = (1/2) [-3(-4 + 3) - 2(-3 -1) + 4(1 + 4)]
ar(∆ABC) = 15.5 units square.
ar(∆ACD) = (1/2) [-3(-3-4) + 4(4-1) + 3(1+4)]
ar(∆ACD) = 22.5 square units.
Area of quadrilateral ABCD = 15.5 + 22.5
= 38 units square.
BE Brainly..........................
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