Question

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If sin 50° = Cot 40° where 50° and 40° are acute angle show that theta = 10°.


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Answer 1

Answer:

According to the question,

sin50=cos40

Now,

cos(90-50)=cos40

We also know,that

if cosA=cosB

then A=B

Now,

90°-5theta=4theta

90°=4theta+5theta

90°=9theta

theta=90°/9

theta=10°

(sorry...I was not able to find the theta sign in my keyboard but solution is correct)

Answer 2

Answer:

given in the question

sin50 theta=cot 40 theta

Step-by-step explanation:

now

cos (90-40)=cos 40 theta

we know that

cosA=cosB

so A=B

so equation ,

90theta-4theta=5 theta

90theta=5theta+4theta

90 theta=9theta

90theta/9theta =10 theta