100 points! Please answer ASAP! Test test! Please!
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14
I'm getting 1. I've done multiple identities in same step so if you have doubt feel free to ask.
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Divyankasc:
I always forget to use that while solving! Hah! Well, thanks for the thousandth time!! :P :D
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8
we know ,
log ( a base b ) = 1/log ( b base a )
use this concept here ,
[ 81 ^{1/log (9 base 5 )} + 3^{3/log ( 3 base√6 ) } ]/409.[ (√7)^{2/log(7 base 25)} - (125)^{log ( 6 base 25) }
solution :-
81^{1/log(9 base 5)
= (9²)^{log( 5 base 9)
= 9^{ log5² base 9 )
= 25
3^{ 3/log(3 base √6 )
=3^{3log( √6 base 3) }
=3^{ log(√6³ base 3)
=√6³
=6√6
(√7)^{ 2/log(7 base 25) }
=(√7)^{2log(25 base 7)
=(7)^{2×1/2log(25 base 7)}
=(7)^{log(25 base 7) }
=25
(125)^{log( 6 base 25 )
=(5³)^{log ( 6 base 5² )
=(5)^{3/2log( 6 base 5)
= (6)^3/2
=6√6
now,
put all calculated value in question ,
=(25 + 6√6)(25 -6√6)/409
=(625 -216)/409
=409/409
= 1
hence , answer is 1
log ( a base b ) = 1/log ( b base a )
use this concept here ,
[ 81 ^{1/log (9 base 5 )} + 3^{3/log ( 3 base√6 ) } ]/409.[ (√7)^{2/log(7 base 25)} - (125)^{log ( 6 base 25) }
solution :-
81^{1/log(9 base 5)
= (9²)^{log( 5 base 9)
= 9^{ log5² base 9 )
= 25
3^{ 3/log(3 base √6 )
=3^{3log( √6 base 3) }
=3^{ log(√6³ base 3)
=√6³
=6√6
(√7)^{ 2/log(7 base 25) }
=(√7)^{2log(25 base 7)
=(7)^{2×1/2log(25 base 7)}
=(7)^{log(25 base 7) }
=25
(125)^{log( 6 base 25 )
=(5³)^{log ( 6 base 5² )
=(5)^{3/2log( 6 base 5)
= (6)^3/2
=6√6
now,
put all calculated value in question ,
=(25 + 6√6)(25 -6√6)/409
=(625 -216)/409
=409/409
= 1
hence , answer is 1
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