Math, asked by jacypauls90, 1 year ago

100 POINTS PLEASE HELP WILL MARK BRAINIEST IF 100% RIGHT
1.) Use the distributive Property to simplify the expression .
(-1)(4 - c)
A. 4 - c
B. -4 + c
C. 4 + c
D.-4 - c

2.)Use the distributive Property to simplify the expression
4(2x - 4)
A.8x + 4
B.8x - 4
C.8x - 16
D.4x - 16

3.) Use the distributive Property to simplify the expression
(10 + 4y) 1/2
A. 5 + 2y
B. 20 + 8y
C. 5 + 4y
D. 10 +2y

4.) To which subsets of real numbers does the number - 22 belong ? Choose all that apply (2 points)

A.Whole numbers
B.Rational numbers
C. Integers
D. Irrational numbers
E. Natural numbers

5.)What is an algebraic expression for the following word phrase: "6 times the difference of b and p" ?

A. 6b - p
B. 6(b - p)
C. 6 - bp
D. 6bp

6.)What is the simplified form of the expression ?

5(14 - 2)^2
------------------
2

A. 60
B. 30
C. 72
D. 360

7.) Evaluate u + xy, if u = 18, x = 10, and y = 8

A.188
B.36
C.98
D.224

8. A square field has an area of 479 ft^2 . What is the approximate length of a side of the field ? Give your answer to the nearest foot . Explain your response .

9. Simplify the expression (7 + 5) + 4 x 13 - 2 Show work .

Answers

Answered by niti117
4
1 b
2 c
3 a
4 b
5 b
6 d
7 c

8 ..
 \sqrt{479} = 21.88ft ^{2}

9 acc to BODMAS

BRACKET
12+4×13-2
=12+52-2
=62

jacypauls90: u only went to 8
jacypauls90: btw im srry i just really need to get an A rn
niti117: never mind
jacypauls90: lmao ok
niti117: hope it helped u child
niti117: hmn
niti117: plz do me a favour dear
niti117: plz click thanku icon for me...hope it do not minds u
jacypauls90: ok
niti117: sweet of u
Answered by webstar0
3
1)B
2)C
3)A
4)B and C
5)B
6)none of these
7)C
8)22 ft
9)(7+5)+4*13-2
=(12)+4*13-2
=12+52-2
=64-2
=62

niti117: thus ans is most probably b
niti117: for ques no 4
jacypauls90: he was right
jacypauls90: 6=D
niti117: ya i marked that ans
niti117: u may jst chk the web ... rational no. include integers as well perhaps most probabke ans be b
niti117: else u wish dear
niti117: probable**
webstar0: ok
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