Question

100 points question
1 litre of a mixture of CO and CO2 is taken. This mixture is passed through a tube containing red hot charcoal. The volume now becomes 1.6 litres. The volumes are measured under the same condition. Find the composition of the mixture by volume.

Answer 1

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Answer 2

Heya,

Here's your answer
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Solution:⬇️

First Of All,
Let the volume of “CO” = $a \: litres$

And....another's volume will be as “CO2” = $b \: litres$

Now, a + b = 1

When it is passed through Charcoal tube, only “CO2” will react.

So,

CO2 + C = 2COb $litres,$$2b \: litres$

Now, $a + 2b = 1.6$
=> $a + b = 1$

Thus, $b = 0.6 \: litres$
=> $a \: = \: 0.4 \: litres$

Ans:⬇️

Hence, b = 0.6 (60%), a = 0.4, (40%)

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