Question

100 points!


Solve equation by using the quadratic formula, round your answer to 3 significant figures where necessary.

Take particular note of the coefficient of x^2

Q. 2x^2-4x+1=0

don't spam

Answer 1

Answer :-

Given quadratic equation

$2 x^2 - 4x + 1 = 0$

Then as we know quadratic equation

= $\frac{-b± \sqrt{ b^2 - 4ac}}{2a}$

Then by putting values in it

b = -4

a = 2

c = 1

= $\frac{-(-4)± \sqrt{ (-4)^2 - 4× 2 × 1}}{2 × 2}$

= $\frac{4± \sqrt{ 16 - 8}}{4}$

= $\frac{4± \sqrt{ 8}}{4}$

= $\frac{4± 2\sqrt{ 2}}{4}$

= $\frac{4± 2.828}{4}$

Then values of x

= $\frac{4+ 2.828}{4}$

= $\frac{6.828}{4}$

= 1.707

And

= $\frac{4 - 2.828}{4}$

= $\frac{1.172}{4}$

= 0.293

Hope it helps

Answer 2

》》》》》hey mate here is your answer.

■□■□■□■□■□■□■□■

2 x^2 - 4x + 1 = 0

Then as we know quadratic equation

= \frac{-b± \sqrt{ b^2 - 4ac}}{2a}

Then by putting values in it

b = -4

a = 2

c = 1

= \frac{-(-4)± \sqrt{ (-4)^2 - 4× 2 × 1}}{2 × 2}

= \frac{4± \sqrt{ 16 - 8}}{4}

= \frac{4± \sqrt{ 8}}{4}

= \frac{4± 2\sqrt{ 2}}{4}

= \frac{4± 2.828}{4}

Then values of x

= \frac{4+ 2.828}{4}

= \frac{6.828}{4}

= 1.707

And

= \frac{4 - 2.828}{4}

= \frac{1.172}{4}

= 0.293

■□■□■□■□■□■□■□■

Thank you...