Question

100 points solve this don’t give silly answers spend time

Answer 1

Answer:

$\huge \sf{1st \: answer}$

Given that,

p = a² b³

Given that,

p = a² b³

q = a³ b

We have to prove that,

L.C.M (p,q) x H.C.F (p,q) = p q

Proof:

Since,

p = a² b³

p = a.a.b.b.b

q = a³ b

q = a.a.a.b

H.C.F (p,q) = a.a.b

H.C.F (p,q) = a² b

L.C.M (p,q) = a.a.a.b.b.b

L.C.M (p,q) = a³ b³

Now, we prove that,

L.C.M (p,q) x H.C.F (p,q) = p q

L.H.S = L.C.M (p,q) x H.C.F (p,q) 

L.H.S = (a³ b³) x (a² b)

L.H.S = a⁵ b⁴

R.H.S = (a² b³) x (a³ b)

R.H.S = a⁵ b⁴

which shows that L.H.S = R.H.S

Hence proved.

Thanks.

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$\huge \bold{2nd \: answer}$

we have to show that

13 ×31 ×41 ×63+41 is a composite number(first separate the common numbers)41(13 ×31 ×1 ×63+1)41(25390)41 ×25390therefore the given number is composite number(factor of only prime numbers)

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Answer 2

Answer:

Hope it works........................................™✌️✌️