Question

☑100 points☑

value of tan132°= ?​

Answer 1

$\sf{\underline{Answer:}}$

$\boxed{\sf{tan\:132 \degree = -1.11061}}$

The tan of 132 degrees is -1.11061.

$\sf{\underline{Note\:that:}}$

tan 132° is periodic.

$\boxed{\sf{tan\:(132\degree + n \times 180\degree) = tan\:132\degree}}$

$\sf{\underline{Note:}}$ n ε Z

$\sf{\underline{Since:}}$

The angle is greater than 90° and less than or equal to 180°, it is located in Quadrant II.

$\sf{\underline{In\:the\:second\:quadrant:}}$

$\implies$ Values for sin are positive.

$\implies$ 132 is an obtuse angle.

$\implies$ Since, it is greater than 90°.

Answer 2

Answer:

the answer is 11/15 π