Question

(100)
The value of <> [x]
[x] dx​

Answer 1

Step-by-step explanation:

=∫

0

100

[tan

−1

x]dx=∫

0

tan1

[tan

−1

x]dx+∫

tan1

100

[tan

−1

x]dx

For 0

⇒[tan

−1

x]=0 ...(1)

And for tan1

⇒[tan

−1

x]=1 ...(2)

From (1) and (2), we get

I=∫

0

tan1

0.dx+∫

tan1

100

1.dx=0+x∣

tan