Question

1000 computer , 99% work on hardware,50% work on cpu, both are independent sets. What is the percentage where both work together?

Answer 1

1000 computers...1% = 10 computers

99% work on hardware..i.e.990 computers

50% works on cpu....i.e. 550 computers

n (A U B) = n(A)+n(B)-n(A ¿ B)

1000 = 900 + 500 - x

1000 = 1400 -x

-400 = -x

x =400

Answer 2

Total computer = 1000

99% of computers = 99/100×1000

= 990 computers

now,50% of computers = 50/100×1000

= 500 computers

total% =

990+500/1000×100

= 149 %

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