Question

1000 g sample of NaOH contains 3 moles of O atoms. what is the percent. purity of NaOH

Answer 1

HEY GO THROUGH THE FOLLOWING ATTATCHMENT:

Answer 2

Answer: The percentage purity of NaOH in the given amount of sample is 12%.

Explanation:

NaOH is the chemical formula for sodium hydroxide.

1 mole of oxygen atoms are contained in 1 mole of NaOH sample.

So, 3 moles of oxygen atoms will be contained in = $\frac{1}{1}\times 3=3moles$ of NaOH sample.

• To calculate the mass, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of NaOH = 3 moles

Molar mass of NaOH = 40 g/mol

Putting values in above equation, we get:

$3=\frac{\text{Mass of NaOH}}{40g/mol}\\\\\text{Mass of NaOH}=120g$

• To calculate the percentage purity, we use the equation:

$\%\text{ purity}=\frac{\text{Mass of pure sample}}{\text{Mass of sample}}\times 100$

Mass of pure sample of NaOH = 120 g

Mass of sample = 1000 g

Putting values in above equation, we get:

$\%\text{ purity of NaOH}=\frac{120g}{1000g}\times 100=12\%$

Hence, the percentage purity of NaOH in the given amount of sample is 12%.