₹1000 is invested at annual rate of 10% p. a. the amount after 2 years compounding is done annually
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Answer:
p= ₹1000
r%=10%
t=2yrs
A= p(1+r/100)^t
A=100(1+10/100)^2
=100(1+1/10)^2
=100(10/10{LCM}+1/10)^2
=100(11/10)^2
=100 × 11/10×11/10
=11×11=121
A=₹121
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