Math, asked by aryaanair3105, 11 months ago

₹1000 is invested at annual rate of 10% p. a. the amount after 2 years compounding is done annually

Answers

Answered by navneettripathi2005
1

Answer:

p= ₹1000

r%=10%

t=2yrs

A= p(1+r/100)^t

A=100(1+10/100)^2

=100(1+1/10)^2

=100(10/10{LCM}+1/10)^2

=100(11/10)^2

=100 × 11/10×11/10

=11×11=121

A=₹121

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