Question

1000 kg block is having speed 1000 cm/s. if block comes to rest in 100 sec, then find out value of force is acting on block ? ​

Answer 1

ᎯᏁᏕᏯᎬᏒ

Given:-

Mass (m) = 1000 kg

Initial velocity (u) =1000cm/s= 10 m/s

Final velocity (v) = 0

Time taken (t) = 100 s

To find:-

Force (F)

Solution:-

$\star~ \boxed{ \rm\purple {F = m \times \frac{ (v - u)}{t} }}$

$⟹ \rm F = 1000 \times \frac{(0 - 10)}{100}$

$⟹\rm F = 1000 \times \frac{( - 10)}{100}$

$\therefore \: \: \rm \red {F = - 100N}$

Answer 2

Answer:

pls mark as brainliest and follow me