1000 ml of 10–1 molar HCl solution is electrolysed after passing 0.02 F charge. Calculate the change in pH of solution. (Given log2 = 0.3) (Assume Cl2 is liberated at anode)
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· Calculate the change in pH of solution. (Given log2 = 0.3) (Assume Cl2 is liberated at anode).
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Answer:
0.1
Explanation: sorry for the explanation
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